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Day 41 of LeetCode Challenge

Published
3 min read
Day 41 of LeetCode Challenge
T

Cloud and DevOps Engineer with hands-on expertise in AWS, CI/CD pipelines, Docker, Kubernetes, and Monitoring tools. Adept at building and automating scalable, fault-tolerant cloud infrastructures, and consistently improving system performance, security, and reliability in dynamic environments.

Problem 1: Permutations

Link to the problem: https://leetcode.com/problems/permutations/

class Solution {
    public List<List<Integer>> permute(int[] nums){
        List<List<Integer>> res = new ArrayList<>();
        backtrack(nums, 0, res);
        return res;
    }

    private void backtrack(int[] nums, int start, List<List<Integer>> res){
        if(start == nums.length){
            res.add(arrayToList(nums));
            return;
        }
        for(int i = start; i < nums.length; i++){
            swap(nums, start, i);
            backtrack(nums, start + 1, res);
            swap(nums, start, i);
        }
    }

    private List<Integer> arrayToList(int[] arr){
        List<Integer> list = new ArrayList<>();
        for(int num : arr) list.add(num);
        return list;
    }

    private void swap(int[] nums, int i, int j){
        int temp = nums[i];
        nums[i] = nums[j];
        nums[j] = temp;
    }
}

Problem 2: Letter Combination of a Phone

Link to the problem: https://leetcode.com/problems/letter-combinations-of-a-phone-number/

class Solution {
    static HashMap<Character, char[]> map = new HashMap<>();
    static List<String> res = new ArrayList<>();
    public List<String> letterCombinations(String digits) {
        res.clear();
        if(digits == null || digits.length() == 0) return res;
        map.put('2', new char[]{'a', 'b', 'c'});
        map.put('3', new char[]{'d', 'e', 'f'});
        map.put('4', new char[]{'g', 'h', 'i'});
        map.put('5', new char[]{'j', 'k', 'l'});
        map.put('6', new char[]{'m', 'n', 'o'});
        map.put('7', new char[]{'p', 'q', 'r', 's'});
        map.put('8', new char[]{'t', 'u', 'v'});
        map.put('9', new char[]{'w', 'x', 'y', 'z'});
        helper("", digits, 0);
        return res;
    }
    private void helper(String str, String digits, int i){
        if(digits.length()==0){
            res.add(str);
            return;
        }
        char[] charray = map.get(digits.charAt(0));
        if(i>=charray.length) return;
        helper(str.concat(Character.toString(charray[i])), digits.substring(1), 0);
        helper(str, digits, i+1);
    }
}

Problem 3: Generate Parentheses

Link to the problem: https://leetcode.com/problems/generate-parentheses/

class Solution {
    public List<String> generateParenthesis(int n) {
        List<String> res = new ArrayList<>();
        helper(res, "", n, 0);
        return res;
    }
    private void helper(List<String> res, String str, int n, int m){
        if(n==0 && m==0){
            res.add(str);
            return;
        }
        if(m==0){
            helper(res, str.concat("("), n-1, 1);
            return;
        }
        if(n==0){
            while(m--!=0)
                str = str.concat(")");
            res.add(str);
            return;
        }
        helper(res, str.concat("("), n-1, m+1);
        helper(res, str.concat(")"), n, m-1);
        return;
    }
}

Problem 4: Delete Nodes From Linked List Present in Array

Link to the problem: https://leetcode.com/problems/delete-nodes-from-linked-list-present-in-array/

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode() {}
 *     ListNode(int val) { this.val = val; }
 *     ListNode(int val, ListNode next) { this.val = val; this.next = next; }
 * }
 */
class Solution {
    public ListNode modifiedList(int[] nums, ListNode head) {
        if(head==null) return null;
        HashMap<Integer, Integer> map = new HashMap<>();
        for(int i:nums) map.put(i, 0);
        while(head!=null && map.containsKey(head.val)) head = head.next;
        ListNode ptr = head;
        while(ptr!=null && ptr.next!=null){
            if(map.containsKey(ptr.next.val)) ptr.next = ptr.next.next;
            else ptr = ptr.next; 
        }
        return head;
    }
}

Problem 5: Next Permutation

Link to the problem: https://leetcode.com/problems/next-permutation/

class Solution {
    public void nextPermutation(int[] nums){
        int i = nums.length - 1;
        while(i > 0 && nums[i - 1] >= nums[i]) i--;
        if(i == 0){
            reverse(nums, 0, nums.length - 1);
            return;
        }
        int j = nums.length - 1;
        while(j >= i && nums[j] <= nums[i - 1]) j--;
        swap(nums, i - 1, j);
        reverse(nums, i, nums.length - 1);
    }

    private void swap(int[] nums, int i, int j){
        int temp = nums[i];
        nums[i] = nums[j];
        nums[j] = temp;
    }

    private void reverse(int[] nums, int start, int end){
        while (start < end){
            int temp = nums[start];
            nums[start] = nums[end];
            nums[end] = temp;
            start++;
            end--;
        }
    }
}